9y^2-12+2=0

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Solution for 9y^2-12+2=0 equation:



9y^2-12+2=0
We add all the numbers together, and all the variables
9y^2-10=0
a = 9; b = 0; c = -10;
Δ = b2-4ac
Δ = 02-4·9·(-10)
Δ = 360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{360}=\sqrt{36*10}=\sqrt{36}*\sqrt{10}=6\sqrt{10}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{10}}{2*9}=\frac{0-6\sqrt{10}}{18} =-\frac{6\sqrt{10}}{18} =-\frac{\sqrt{10}}{3} $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{10}}{2*9}=\frac{0+6\sqrt{10}}{18} =\frac{6\sqrt{10}}{18} =\frac{\sqrt{10}}{3} $

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